A car is accelerated uniformly from rest until reaches speed of 30 m/s in 10 seconds. After traveling

A car is accelerated uniformly from rest until reaches speed of 30 m/s in 10 seconds. After traveling with constant speed for 15 seconds, it stops with uniform negatif acceleration in 6 seconds. Determine the total distance when the car moves!

Discussion:
Known:
    v0 = 0 (rest)
    v1 = 30 m/s
    t0-1 = 10 s
    v2 = 30 m/s
    t2 = 15 – 10 = 5 s
    v3 = 0 (rest)
    t3 = 6 s

Asked:
    S = …. ?

Answered:
Total distance when the car moves can be calculated with this formula:
So, the total distance when the car moves is 390 m.

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