tan (7x + 2/3π) = 1/3√3, 0 ≤ x ≤ 2π
Tentukan himpunan penyelesaian dari persamaan trigonometri berikut!
tan (7x + 2/3π) = 1/3√3, 0 ≤ x ≤ 2π
Jawab:
tan (7x + 2/3π) = 1/3√3 = tan 1/6π
7x + 2/3π = 1/6π + k . π
7x = 1/6π - 2/3π + k . π
7x = - ½π + k . π
x = - 1/14π + k . π
Jadi, himpunan penyelesaiannya adalah {1/14π, 3/14π, 5/14π, ½π, 9/14π, 11/14π, 13/14π, 15/14π, 17/14π, 19/14π, 3/2π, 23/14π, 25/14π, 27/14π}
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