Jika f(x) = 4 cos (3x – π), nilai f’(π/2) =
Jika f(x) = 4 cos (3x – π), nilai f’(π/2) = ….
A. -12
B. -6
C. 0
D. 6
E. 12
Pembahasan:
f(x) = 4 cos (3x – π)
Turunan pertama:
f'(x) = 4 (-3) sin (3x – π)
f'(x) = -12 sin (3x – π)
Jawaban: A
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