Diketahui f(x) = 2x + 1, g(x) = 5 – 3x , h(x) = x2 – 1 Tentukan:
Diketahui f(x) = 2x + 1, g(x) = 5 – 3x , h(x) = x2 – 1
Tentukan:
A. (fogoh) (x) =
B. (fog) (-2) =
C. (gofoh) (3) =
Jawab:
A. (goh)(x) = 5 – 3(x2 – 1) = 8 – 3x2
(fogoh) (x) = 2(8 – 3x2) + 1
(fogoh) (x) = 17 – 6x2
B. (fog)(x) = 2(5 – 3x) + 1
= 11 – 6x
(fog)(-2) = 11 – 6(-2) = 23
C. (foh)(x) = 2(x2 – 1) + 1 = 2x2 – 1
(gofoh)(x) = 5 – 3(2x2 – 1)
(gofoh)(x) = 8 – 6x2
(gofoh)(3) = 8 – 6(32) = 8 – 54 = -46
----------------#----------------
Semoga Bermanfaat
Jangan lupa komentar & sarannya
Email: nanangnurulhidayat@gmail.com
Kunjungi terus: masdayat.net OK! 😁
Post a Comment for "Diketahui f(x) = 2x + 1, g(x) = 5 – 3x , h(x) = x2 – 1 Tentukan:"