Diketahui f(x) = 3x2 + 4x - 5 dan (f - g) (x) = x2 - x + 3. Tentukan

Diketahui f(x) = 3x² + 4x - 5 dan (f - g) (x) = x² - x + 3. Tentukan:

a. g(x)

b. f(-1) dan g(-1)

c. (f + g)(-1) dan (f - g)(-1)

d. (f × g)(-1) dan (f/g)(-1)

Jawab:

f(x) = 3x² + 4x – 5

(f – g) (x) = x² – x + 3

a. (f – g) (x) = x² – x + 3

f(x) – g(x) = x² – x + 3

g(x) = f(x) – (x² – x + 3)

= 3x² + 4x – 5 – x² + x – 3

g(x) = 2x² + 5x – 8

b. f(-1) = 3(-1)² + 4(-1) – 5 = 3 – 4 – 5 = -6

g(-1) = 2(-1)² + 5(-1) – 8 = 2 – 5 – 8 = -11

c. (f + g)(-1) = f(-1) + g(-1) = -6 + (-11) = -17

(f – g)(-1) = f(-1) – g(-1) = -6 - (-11) = 5

d. (f × g)(-1) = f(-1) × g(-1) = (-6) × (-11) = 66

(f/g)(-1) = f(-1)/g(-1) = (-6)/(-11) = 6/11

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